Which of the statement is incorrect for the given paragraph?
Simple salt $\xrightarrow{\text{Flame test}}$ Golden yellow flame
Simple salt $\xrightarrow[MnO_2]{Conc. H_2SO_4} (X)$ Yellowish green gas
Simple salt $\xrightarrow{AgNO_3} (Z)$ White ppt. (Insoluble in dil. $HNO_3$)
Simple salt $\xrightarrow[Conc. H_2SO_4]{K_2Cr_2O_7} (Y)$ Reddish brown vapour

  • A
    $(X)$ when reacted with excess of $NH_3$ then one of the product is explosive in nature
  • B
    When $(Y)$ passed in $NaOH$ solution yellow solution is formed
  • C
    $(Z)$ does not give chromyl chloride test
  • D
    $(X)$ can be formed by oxidation of $HCl$ with $O_2$ in the presence of $CuCl_2$ as catalyst

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Similar Questions

Match List-$I$ with List-$II$:
List-$I$ (Anion) List-$II$ (Gas evolved on reaction with dil. $H_2SO_4$)
$A. CO_3^{2-}$ $I$. Colourless gas which turns lead acetate paper black
$B. S^{2-}$ $II$. Colourless gas which turns acidified potassium dichromate solution green
$C. SO_3^{2-}$ $III$. Brown fumes which turn acidified $KI$ solution containing starch blue
$D. NO_2^{-}$ $IV$. Colourless gas evolved with brisk effervescence,which turns lime water milky

Choose the correct answer from the options given below:

$A$ brown ring appears in the test for

$A$ sodium salt on treatment with $MgCl_2$ gives white precipitate only on heating. The anion of the sodium salt is

An anion solution gives a white precipitate with $AgNO_3$ solution. The precipitate dissolves in dilute ammonia due to the formation of:

$A$ substance on treatment with dilute $H_2SO_4$ liberates a colourless gas which produces:
$(i)$ turbidity with baryta water and
$(ii)$ turns acidified dichromate solution green.
The reaction indicates the presence of:

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